Which of the following has been arranged in o | vedclass

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(C) To determine the order,calculate the oxidation number $(ON)$ of nitrogen in each species:$NH_4^+$: $x + 4(+1) = +1 \implies x = -3$$N_2H_4$: $2x +

Vedclass · Accepted Answer

$NH_4^+ < N_2H_4 < NH_2OH < N_2O$

Vedclass · Answer

(C) To determine the order,calculate the oxidation number $(ON)$ of nitrogen in each species:$NH_4^+$: $x + 4(+1) = +1 \implies x = -3$$N_2H_4$: $2x + 4(+1) = 0 \implies 2x = -4 \implies x = -2$$NH_2OH$: $x + 2(+1) + (-2) + (+1) = 0 \implies x + 1 = 0 \implies x = -1$$N_2O$: $2x + (-2) = 0 \implies 2x = +2 \implies x = +1$Thus,the increasing order is: $\mathop {NH_4^+}\limits_{(-3)} < \mathop {N_2H_4}\limits_{(-2)} < \mathop {NH_2OH}\limits_{(-1)} < \mathop {N_2O}\limits_{(+1)}$.

Compound	Oxidation number
$1$. $C_6H_{12}O_6$ (Carbon)	$a$. $+1$
$2$. $CCl_4$ (Carbon)	$b$. $0$
$3$. $NH_4Cl$ (Nitrogen)	$c$. $+4$
$4$. $Ba(H_2PO_2)_2$ (Phosphorus)	$d$. $-3$

Which of the following has been arranged in order of increasing oxidation number of nitrogen?

Similar Questions

The oxidation number of carbon in $CH_2O$ is

Match the following compounds with the oxidation number of the central atom (or specific atom in question):

Compound Oxidation number

$1$. $C_6H_{12}O_6$ (Carbon) $a$. $+1$

$2$. $CCl_4$ (Carbon) $b$. $0$

$3$. $NH_4Cl$ (Nitrogen) $c$. $+4$

$4$. $Ba(H_2PO_2)_2$ (Phosphorus) $d$. $-3$

If $M$ is the molecular weight of $KMnO_4$,what will be its equivalent weight when it is converted into $K_2MnO_4$?

What is the oxidation number of $Mn$ in $MnO_{4}^{2-}$ ion?

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